Integrand size = 15, antiderivative size = 93 \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=-\frac {b^2 \sqrt {a+\frac {b}{x}} x}{8 a^2}+\frac {b \sqrt {a+\frac {b}{x}} x^2}{12 a}+\frac {1}{3} \sqrt {a+\frac {b}{x}} x^3+\frac {b^3 \text {arctanh}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right )}{8 a^{5/2}} \]
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Time = 0.03 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {272, 43, 44, 65, 214} \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=\frac {b^3 \text {arctanh}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right )}{8 a^{5/2}}-\frac {b^2 x \sqrt {a+\frac {b}{x}}}{8 a^2}+\frac {1}{3} x^3 \sqrt {a+\frac {b}{x}}+\frac {b x^2 \sqrt {a+\frac {b}{x}}}{12 a} \]
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Rule 43
Rule 44
Rule 65
Rule 214
Rule 272
Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {\sqrt {a+b x}}{x^4} \, dx,x,\frac {1}{x}\right ) \\ & = \frac {1}{3} \sqrt {a+\frac {b}{x}} x^3-\frac {1}{6} b \text {Subst}\left (\int \frac {1}{x^3 \sqrt {a+b x}} \, dx,x,\frac {1}{x}\right ) \\ & = \frac {b \sqrt {a+\frac {b}{x}} x^2}{12 a}+\frac {1}{3} \sqrt {a+\frac {b}{x}} x^3+\frac {b^2 \text {Subst}\left (\int \frac {1}{x^2 \sqrt {a+b x}} \, dx,x,\frac {1}{x}\right )}{8 a} \\ & = -\frac {b^2 \sqrt {a+\frac {b}{x}} x}{8 a^2}+\frac {b \sqrt {a+\frac {b}{x}} x^2}{12 a}+\frac {1}{3} \sqrt {a+\frac {b}{x}} x^3-\frac {b^3 \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,\frac {1}{x}\right )}{16 a^2} \\ & = -\frac {b^2 \sqrt {a+\frac {b}{x}} x}{8 a^2}+\frac {b \sqrt {a+\frac {b}{x}} x^2}{12 a}+\frac {1}{3} \sqrt {a+\frac {b}{x}} x^3-\frac {b^2 \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+\frac {b}{x}}\right )}{8 a^2} \\ & = -\frac {b^2 \sqrt {a+\frac {b}{x}} x}{8 a^2}+\frac {b \sqrt {a+\frac {b}{x}} x^2}{12 a}+\frac {1}{3} \sqrt {a+\frac {b}{x}} x^3+\frac {b^3 \tanh ^{-1}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right )}{8 a^{5/2}} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.75 \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=\frac {\sqrt {a} \sqrt {a+\frac {b}{x}} x \left (-3 b^2+2 a b x+8 a^2 x^2\right )+3 b^3 \text {arctanh}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right )}{24 a^{5/2}} \]
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Time = 0.03 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.04
method | result | size |
risch | \(\frac {\left (8 a^{2} x^{2}+2 a b x -3 b^{2}\right ) x \sqrt {\frac {a x +b}{x}}}{24 a^{2}}+\frac {b^{3} \ln \left (\frac {\frac {b}{2}+a x}{\sqrt {a}}+\sqrt {a \,x^{2}+b x}\right ) \sqrt {\frac {a x +b}{x}}\, \sqrt {x \left (a x +b \right )}}{16 a^{\frac {5}{2}} \left (a x +b \right )}\) | \(97\) |
default | \(\frac {\sqrt {\frac {a x +b}{x}}\, x \left (16 \left (a \,x^{2}+b x \right )^{\frac {3}{2}} a^{\frac {5}{2}}-12 \sqrt {a \,x^{2}+b x}\, a^{\frac {5}{2}} b x -6 \sqrt {a \,x^{2}+b x}\, a^{\frac {3}{2}} b^{2}+3 \ln \left (\frac {2 \sqrt {a \,x^{2}+b x}\, \sqrt {a}+2 a x +b}{2 \sqrt {a}}\right ) a \,b^{3}\right )}{48 \sqrt {x \left (a x +b \right )}\, a^{\frac {7}{2}}}\) | \(115\) |
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Time = 0.28 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.63 \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=\left [\frac {3 \, \sqrt {a} b^{3} \log \left (2 \, a x + 2 \, \sqrt {a} x \sqrt {\frac {a x + b}{x}} + b\right ) + 2 \, {\left (8 \, a^{3} x^{3} + 2 \, a^{2} b x^{2} - 3 \, a b^{2} x\right )} \sqrt {\frac {a x + b}{x}}}{48 \, a^{3}}, -\frac {3 \, \sqrt {-a} b^{3} \arctan \left (\frac {\sqrt {-a} \sqrt {\frac {a x + b}{x}}}{a}\right ) - {\left (8 \, a^{3} x^{3} + 2 \, a^{2} b x^{2} - 3 \, a b^{2} x\right )} \sqrt {\frac {a x + b}{x}}}{24 \, a^{3}}\right ] \]
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Time = 4.79 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.31 \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=\frac {a x^{\frac {7}{2}}}{3 \sqrt {b} \sqrt {\frac {a x}{b} + 1}} + \frac {5 \sqrt {b} x^{\frac {5}{2}}}{12 \sqrt {\frac {a x}{b} + 1}} - \frac {b^{\frac {3}{2}} x^{\frac {3}{2}}}{24 a \sqrt {\frac {a x}{b} + 1}} - \frac {b^{\frac {5}{2}} \sqrt {x}}{8 a^{2} \sqrt {\frac {a x}{b} + 1}} + \frac {b^{3} \operatorname {asinh}{\left (\frac {\sqrt {a} \sqrt {x}}{\sqrt {b}} \right )}}{8 a^{\frac {5}{2}}} \]
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Time = 0.29 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.47 \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=-\frac {b^{3} \log \left (\frac {\sqrt {a + \frac {b}{x}} - \sqrt {a}}{\sqrt {a + \frac {b}{x}} + \sqrt {a}}\right )}{16 \, a^{\frac {5}{2}}} - \frac {3 \, {\left (a + \frac {b}{x}\right )}^{\frac {5}{2}} b^{3} - 8 \, {\left (a + \frac {b}{x}\right )}^{\frac {3}{2}} a b^{3} - 3 \, \sqrt {a + \frac {b}{x}} a^{2} b^{3}}{24 \, {\left ({\left (a + \frac {b}{x}\right )}^{3} a^{2} - 3 \, {\left (a + \frac {b}{x}\right )}^{2} a^{3} + 3 \, {\left (a + \frac {b}{x}\right )} a^{4} - a^{5}\right )}} \]
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Time = 0.30 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.99 \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=-\frac {b^{3} \log \left ({\left | 2 \, {\left (\sqrt {a} x - \sqrt {a x^{2} + b x}\right )} \sqrt {a} + b \right |}\right ) \mathrm {sgn}\left (x\right )}{16 \, a^{\frac {5}{2}}} + \frac {b^{3} \log \left ({\left | b \right |}\right ) \mathrm {sgn}\left (x\right )}{16 \, a^{\frac {5}{2}}} + \frac {1}{24} \, \sqrt {a x^{2} + b x} {\left (2 \, {\left (4 \, x \mathrm {sgn}\left (x\right ) + \frac {b \mathrm {sgn}\left (x\right )}{a}\right )} x - \frac {3 \, b^{2} \mathrm {sgn}\left (x\right )}{a^{2}}\right )} \]
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Time = 6.14 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.80 \[ \int \sqrt {a+\frac {b}{x}} x^2 \, dx=\frac {x^3\,\sqrt {a+\frac {b}{x}}}{8}+\frac {x^3\,{\left (a+\frac {b}{x}\right )}^{3/2}}{3\,a}-\frac {x^3\,{\left (a+\frac {b}{x}\right )}^{5/2}}{8\,a^2}-\frac {b^3\,\mathrm {atan}\left (\frac {\sqrt {a+\frac {b}{x}}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,1{}\mathrm {i}}{8\,a^{5/2}} \]
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